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Light wave is travelling along +y-direction. If the corresponding E\vec{E} vector at any time is along the +z-axis. Then the direction of B\vec{B} vector at this time is along:

Electromagnetic Waves
NEET
1

y-axis

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+x-axis

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-x-axis

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-z-axis

Solution:

In an electromagnetic wave, the direction of propagation is given by the direction of the Poynting vector, which is parallel to E×B\vec{E} \times \vec{B}. The wave is travelling along the +y-direction, so the direction of propagation is y^\hat{y}. The electric field E\vec{E} is along the +z-axis, so its direction is z^\hat{z}. Let the direction of the magnetic field B\vec{B} be b^\hat{b}. Then, z^×b^\hat{z} \times \hat{b} must be in the direction of y^\hat{y}. Using the right-hand rule or vector cross product properties, we know that z^×x^=y^\hat{z} \times \hat{x} = \hat{y}. Therefore, the direction of B\vec{B} must be along the +x-axis.