The equilibrium constant for the reaction

Zn(s) + Cu²⁺ (aq.) → Cu(s) + Zn²⁺ (aq.), E° = 1.10 V

at 298 K is

Solution:

The relationship between the standard cell potential (E°) and the equilibrium constant (K) at 298 K is given by the equation:

E° = (0.0592/n) log K

For the given reaction, Zn(s) + Cu²⁺ (aq.) → Cu(s) + Zn²⁺ (aq.), the number of electrons transferred (n) is 2.

Given E° = 1.10 V.

Substituting the values into the equation:

1.10 V = (0.0592/2) log K

1.10 = 0.0296 log K

log K = 1.10 / 0.0296

log K ≈ 37.162

K = 10³⁷.¹⁶²

Comparing this value with the given options, the closest value is 10³⁷.²².