If standard reduction potential of three metals, A, B and C are -0.5 V, +1.2 V and -1.5 V respectively, then the order of reducing power of the metals will be

Solution:

The reducing power of a metal is inversely proportional to its standard reduction potential. A lower (more negative) standard reduction potential indicates a stronger reducing agent and thus higher reducing power.

Given standard reduction potentials:

Metal A: -0.5 V

Metal B: +1.2 V

Metal C: -1.5 V

Arranging these potentials in increasing order:

-1.5 V (C) < -0.5 V (A) < +1.2 V (B)

Therefore, the order of reducing power will be the reverse of this order of potentials:

C > A > B

So, metal C has the highest reducing power, followed by A, and then B.