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The active mass of 2 g H₂(g) in 1 L container will be
Solution:
Active mass is defined as the molar concentration of a substance, which is the number of moles per unit volume.
Given:
Mass of H₂ = 2 g
Volume of container = 1 L
Molar mass of H₂ = 2 × (atomic mass of H) = 2 × 1 g/mol = 2 g/mol
Number of moles of H₂ = Mass / Molar mass
Number of moles of H₂ = 2 g / 2 g/mol = 1 mol
Active mass = Number of moles / Volume
Active mass = 1 mol / 1 L = 1 mol/L
Therefore, the active mass of 2 g H₂(g) in a 1 L container will be 1.