Topic : projectile motion

For a particle projected with speed of 20 m/s from ground, the kinetic energy at top most point of trajectory is (1/4)th of the initial kinetic energy. The angle of projection from horizontal is

In a cricket match, a player throws the ball to the wicketkeeper which is at 20 m horizontal distance. The player throws the ball with speed u at angle 45° with the horizontal. The value of u such that wicketkeeper just catches the ball directly, will be

A projectile has the range of 40 m and reaches a maximum height of 10 m. What is angle at which projectile is fired with horizontal?

A ball is projected horizontally with velocity 4 m/s from the top of a building 19.6 m high. The distance of the point from the bottom of the building where ball will hit the ground is ($g = 9.8 \text{ ms}^{-2}$)

For a particle projected from horizontal surface, the ratio of range to maximum height reached is ($\theta$ is angle of projection with vertical)